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**Example text**

43) that p nt (zi , zi+1 ) ≥ c . 41), we obtain pt (x, y) ≥ ... B(x1 ,r) n = = ≥ ≥ cn dμ(zn−1 ) . . dμ(z1 ) V (x, r) V (x1 , r) . . V (xn−1 , r) B(xn−1 ,r) cn c ≥c V (x, r) V x, (t/n)1/β cn V x, t1/β cn nα /β c ≥c 1/β 1/β V x, t V x, (t/n) V x, t1/β c exp (−Cn) V x, t1/β ⎛ 1 ⎞ β−1 β c d (x, y) ⎠. 27). 6. 5, we have E (u) all u ∈ L2 (M ). Consequently, F = W β/2,2 . Eβ (u) for Proof. 2 we have E (u) ≥ cEβ (u). 5), we obtain E (u) ≤ CEβ (u), which ﬁnishes the proof. G. Aronson, Non-negative solutions of linear parabolic equations Ann.

C below), amenability of the groups BA(X) for all ﬁnite sets X (therefore, amenability of all groups generated by bounded automata) would follow from amenability just of all the Mother groups M(X). It is worth noting that the groups generated by bounded automata form a subclass of the class of contracting self-similar groups (see [BN03, Nek05]). It is still an open question whether all contracting groups are amenable. However, Nekrashevych [Nek08] recently established a weaker property: contracting groups contain no free groups with ≥ 2 generators.

9. Given two points x, y ∈ M , a chain connecting x and y is any ﬁnite sequence n {xk }k=0 of points in M such that x0 = x, xn = y. We say that a metric space satisﬁes the chain condition if there is a constant C > 0 such that for any positive integer n and for all x, y ∈ M there is a chain {xk }nk=0 connecting x and y, such that d (x, y) for all k = 0, 1, . . , n − 1. 25) d (xk , xk+1 ) ≤ C n For example, the geodesic distance on any length space satisﬁes the chain condition. On the other hand, the combinatorial distance on a graph does not satisfy it.